The Chicago Cubs set off fireworks offensively on the Fourth of July, as they hit a franchise record eight home runs against the St. Louis Cardinals.
Michael Busch made sure the good times kept rolling on Saturday at Wrigley Field.
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On Friday, he hit three home runs in the 11-3 win. He slammed a solo shot in the second inning, a two-run shot in the third inning and another solo shot in the seventh inning. He finished the game 4-for-4 with five RBI and three runs scored.
On Saturday, at Wrigley Field, he wasted no time at all, hitting his fourth home run in his last five plate appearances, blasting a solo shot in the second inning to cut the Cardinals’ lead to 2-1.
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At the time, it was his 18th home run of the season. And it got better. Busch had hits in his next two at-bats after six innings. That meant he had seven hits in his last seven official at-bats. He also singled and doubled on Saturday.
After homering THREE times yesterday, Michael Busch homers in his first AB today 👀 pic.twitter.com/JyuxASozAJ
— MLB (@MLB) July 5, 2025
By the third at-bat he had boosted his batting average to .296 and his OPS to .945. At the time the Cubs were ahead, 4-3.
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On Friday, four other Cubs hit home runs. Pete Crow-Armstrong — who will start for the National League in the All-Star Game on July 15 — hit two. Seiya Suzuki, Carson Kelly and Dansby Swanson each hit one.
Busch also took an unexpected place in Cubs history according to ESPN.
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By hitting three home runs on Independence Day, he became the third Cubs slugger to do it. All three instances were against the Cardinals.
The other two were Moises Alou on July 4, 2003, and Hank Leiber on July 4, 1939.
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